The findLastIndex() method of TypedArray instances iterates the typed array in reverse order and returns the index of the first element that satisfies the provided testing function. If no elements satisfy the testing function, -1 is returned. This method has the same algorithm as Array.prototype.findLastIndex().
function isNegative(element /*, index, array */) {
return element < 0;
}
const int8 = new Int8Array([10, -20, 30, -40, 50]);
console.log(int8.findLastIndex(isNegative));
// Expected output: 3findLastIndex(callbackFn)
findLastIndex(callbackFn, thisArg)callbackFnA function to execute for each element in the typed array. It should return a truthy value to indicate a matching element has been found, and a falsy value otherwise. The function is called with the following arguments:
elementThe current element being processed in the typed array.
indexThe index of the current element being processed in the typed array.
arrayThe typed array findLastIndex() was called upon.
thisArg OptionalA value to use as this when executing callbackFn. See iterative methods.
The index of the last (highest-index) element in the typed array that passes the test. Otherwise -1 if no matching element is found.
See Array.prototype.findLastIndex() for more details. This method is not generic and can only be called on typed array instances.
The following example returns the index of the last element in the typed array that is a prime number, or -1 if there is no prime number.
function isPrime(n) {
if (n < 2) {
return false;
}
if (n % 2 === 0) {
return n === 2;
}
for (let factor = 3; factor * factor <= n; factor += 2) {
if (n % factor === 0) {
return false;
}
}
return true;
}
let uint8 = new Uint8Array([4, 6, 8, 12]);
console.log(uint8.findLastIndex(isPrime));
// -1 (no primes in array)
uint8 = new Uint8Array([4, 5, 7, 8, 9, 11, 12]);
console.log(uint8.findLastIndex(isPrime));
// 5Note: The isPrime() implementation is for demonstration only. For a real-world application, you would want to use a heavily memoized algorithm such as the Sieve of Eratosthenes to avoid repeated calculations.